#### Answer

$\dfrac{1}{16}$

#### Work Step by Step

Use the rule $\dfrac{a}{b} \div c = \dfrac{a}{b} \times \dfrac{1}{c}$ to obtain:
$\require{cancel}
=\dfrac{3}{8} \times \dfrac{1}{6}
\\=\dfrac{3(1)}{8(6)}
\\=\dfrac{\cancel{3}(1)}{8(\cancel{6}^2)}
\\=\dfrac{1}{8(2)}
\\=\dfrac{1}{16}$