## Elementary Technical Mathematics

$\dfrac{1}{16}$
Use the rule $\dfrac{a}{b} \div c = \dfrac{a}{b} \times \dfrac{1}{c}$ to obtain: $\require{cancel} =\dfrac{3}{8} \times \dfrac{1}{6} \\=\dfrac{3(1)}{8(6)} \\=\dfrac{\cancel{3}(1)}{8(\cancel{6}^2)} \\=\dfrac{1}{8(2)} \\=\dfrac{1}{16}$