Answer
$18$
Work Step by Step
Convert each mixed number to improper fraction to obtain:
$=\dfrac{7(3)+6}{7} \times \dfrac{3(4)+2}{3}
\\=\dfrac{27}{7} \times \dfrac{14}{3}$
Cancel common factors to obtain:
$\require{cancel}
\\=\dfrac{\cancel{27}^9}{\cancel{7}} \times \dfrac{\cancel{14}^2}{\cancel{3}}
\\=\dfrac{9}{1} \times \dfrac{2}{1}
\\=\dfrac{9(2)}{1(1)}
\\=18$
