## Introductory Algebra for College Students (7th Edition)

$\frac{8x+40}{3x-6}$
If there are no common factors that can be eliminated, multiply numerator by numerator and denominator by denominator. $\frac{8}{x-2}\times\frac{x+5}{3}=\frac{8(x+5)}{3(x-2)}=\frac{8x+40}{3x-6}$