Answer
$\displaystyle \frac{x+5}{x}$
Work Step by Step
Step by step multiplication of rational expressions:
1. Factor completely what you can
2. Reduce (divide) numerators and denominators by common factors.
3. Multiply the remaining factors in the numerators and
multiply the remaining factors in the denominators. $(\displaystyle \frac{P}{Q}\cdot\frac{R}{S}=\frac{PR}{QS})$
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Factor what we can:
$x^{2}-25=x^{2}-5^{2}=\qquad $... a difference of squares,
$=(x+5)(x-5)$
$x^{2}-3x-10=...$
... factor the trinomial $x^{2}+bx+c$
... by searching for two factors of $c$ whose sum is $b$.
... Here, we find that $-5$ and $+2 $are factors of $-10$ whose sum is $-3.$
$=(x-5)(x+2)$
The problem becomes
$...=\displaystyle \frac{(x+5)(x-5)\cdot(x+2)}{(x-5)(x+2)\cdot x}\qquad $... divide out the common factors
= $\displaystyle \frac{x+5}{x}$
