Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set: 1

Answer

$\frac{4x-20}{9x+27}$

Work Step by Step

If there are no common factors that can be eliminated, multiply numerator by numerator and denominator by denominator. $\frac{4}{x+3}\times\frac{x-5}{9}=\frac{4(x-5)}{9(x+3)}=\frac{4x-20}{9x+27}$
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