Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set - Page 498: 13

Answer

$\displaystyle \frac{2}{y}$

Work Step by Step

Step by step multiplication of rational expressions: 1. Factor completely what you can 2. Reduce (divide) numerators and denominators by common factors. 3. Multiply the remaining factors in the numerators and multiply the remaining factors in the denominators. $(\displaystyle \frac{P}{Q}\cdot\frac{R}{S}=\frac{PR}{QS})$ --- Factor what we can: $4y+30=2(2y+15)$ $y^{2}-3y=y(y-3)$ The problem becomes $...=\displaystyle \frac{2(2y+15)\cdot(y-3)}{y(y-3)\cdot(2y+15)}\qquad $... divide out the common factors = $\displaystyle \frac{2}{y}$
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