Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set - Page 498: 18

Answer

$3y+12$

Work Step by Step

Step by step multiplication of rational expressions: 1. Factor completely what you can 2. Reduce (divide) numerators and denominators by common factors. 3. Multiply the remaining factors in the numerators and multiply the remaining factors in the denominators. $(\displaystyle \frac{P}{Q}\cdot\frac{R}{S}=\frac{PR}{QS})$ --- Factor what we can: $y^{2}-16=y^{2}-4^{2}=\qquad $... a difference of squares, $=(y+4)(y-4)$ The problem becomes $...=\displaystyle \frac{(y+4)(y-4)\cdot 3}{(y-4)}\qquad $... divide out the common factors $=\displaystyle \frac{(y+4)\fbox{$(y-4)$}\cdot 3}{\fbox{$(y-4)$}}$ $=\displaystyle \frac{(y+4)\cdot 3}{1}$ = $3y+12$
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