Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.3 - Factoring Trinomials Whose Leading Coefficient is Not 1 - Exercise Set - Page 444: 59

Answer

$ 2(x+5)(2x+3) $

Work Step by Step

Factoring by grouping: 1. Multiply the leading coefficient, a, and the constant, c. 2. Find the factors of ac whose sum is b. 3. Rewrite the middle term, bx, as a sum or difference using the factors from step 2. 4. Factor by grouping --- $4x^{2}+26x+30 =...$ Always start by searching for a GCF ... ($GCF=2$). $=2(2x^{2}+13x+15)$ Now, the parentheses: 1. $\quad$"$ac$"$=30 \qquad $ 2. $\quad$sum = $+13\quad$... factors: $+3$ and $+10$ 3. $\quad$ $2x^{2}+13x+15 = (2x^{2}+3\mathrm{x})+(10x+15)$ 4. $\quad$... $= x(2x+3)+(5)(2x+3) = (x+5)(2x+3) $ $2(2x^{2}+13x+15) = 2(x+5)(2x+3) $
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