Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.3 - Factoring Trinomials Whose Leading Coefficient is Not 1 - Exercise Set - Page 444: 50



Work Step by Step

Factoring by grouping: 1. Multiply the leading coefficient, a, and the constant, c. 2. Find the factors of ac whose sum is b. 3. Rewrite the middle term, bx, as a sum or difference using the factors from step 2. 4. Factor by grouping --- $6x^{2}-7xy-5y^{2} =...$ Always start by searching for a GCF ... (there are none other than 1). 1. $\quad ac=-30y^{2} $ 2. $\quad$sum = $-7y\quad$... factors: $-10y$ and $+3y$ 3. $\quad$ $6x^{2}-7xy-5y^{2} = (6x^{2}+3xy)+(-10xy-5y^{2} )$ 4. $\quad$... $= 3x(2x+y)+(-5y)(2x+y) = (3x-5y)(2x+y)$ Check by FOIL $F:\quad 6x^{2}$ $O:\quad +3xy$ $I:\quad -10xy$ $L:\quad -5y^{2}$ $(3x-5y)(2x+y)$ = $6x^{2}-7xy-5y^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.