Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.3 - Factoring Trinomials Whose Leading Coefficient is Not 1 - Exercise Set - Page 444: 51

Answer

$(3x-2y)(5x+7y)$

Work Step by Step

Factoring by grouping: 1. Multiply the leading coefficient, a, and the constant, c. 2. Find the factors of ac whose sum is b. 3. Rewrite the middle term, bx, as a sum or difference using the factors from step 2. 4. Factor by grouping --- $15x^{2}+11xy-14y^{2} =...$ Always start by searching for a GCF ... (there are none other than 1). 1. $\quad ac=-210y^{2} $ 2. $\quad$sum = $+11y\quad$... factors: $-10y$ and $+21y$ 3. $\quad$ $15x^{2}+11xy-14y^{2} = (15x^{2}+21xy)+(-10xy-14y^{2} )$ 4. $\quad$... $= 3x(5x+7y)+(-2y)(5x+7y) = (3x-2y)(5x+7y)$ Check by FOIL $F:\quad 15x^{2}$ $O:\quad +21xy$ $I:\quad -10xy$ $L:\quad -14y^{2}$ $(3x-2y)(5x+7y)$ = $15x^{2}+11xy-14y^{2}$
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