Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.3 - Factoring Trinomials Whose Leading Coefficient is Not 1 - Exercise Set - Page 444: 32

Answer

$ (y+1)(15y-2) $

Work Step by Step

Factoring by grouping: 1. Multiply the leading coefficient, a, and the constant, c. 2. Find the factors of ac whose sum is b. 3. Rewrite the middle term, bx, as a sum or difference using the factors from step 2. 4. Factor by grouping --- $15y^{2}+13y-2 =...$ Always start by searching for a GCF ... (there are none other than 1). 1. $\quad ac=-30\qquad $ 2. $\quad$sum = $+13 \quad$... factors: $+15$ and $-2$ 3. $\quad 15y^{2}+13y-2 = (15y^{2}+15y)+(-2y-2)$ 4. $\quad$... $= 15y(y+1)+(-2)(y+1)=(y+1)(15y-2)$ Check by FOIL $F:\quad 15y^{2}$ $O:\quad -2y$ $I:\quad +15y$ $L:\quad -2$ $ (y+1)(15y-2) $ = $15y^{2}+13y-2$
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