Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.3 - Factoring Trinomials Whose Leading Coefficient is Not 1 - Exercise Set - Page 444: 56

Answer

$ (3a-7b)(a+2b) $

Work Step by Step

Factoring by grouping: 1. Multiply the leading coefficient, a, and the constant, c. 2. Find the factors of ac whose sum is b. 3. Rewrite the middle term, bx, as a sum or difference using the factors from step 2. 4. Factor by grouping --- $3a^{2}-ab-14b^{2} =...$ Always start by searching for a GCF ... (there are none other than 1). 1. $\quad$"$ac$"$=-42b^{2} $ 2. $\quad$sum = $-b\quad$... factors: $-7b$ and $+6b$ 3. $\quad$ $3a^{2}-ab-14b^{2} = (3a^{2}+6ab)+( -7ab-14b^{2})$ 4. $\quad$... $= 3a(a+2b)+(-7b)(a+2b) = (3a-7b)(a+2b) $ Check by FOIL $F:\quad 3a^{2}$ $O:\quad +6ab$ $I:\quad -7ab$ $L:\quad -14b^{2}$ $ (3a-7b)(a+2b) $ = $3a^{2}-ab-14b^{2} $
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