Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.2 - The Multiplication Property of Equality - Exercise Set - Page 130: 60

Answer

The equation specified by the problem is: $-6x = 20$ Solving for $x$ gives us: $x = -\frac{10}{3}$

Work Step by Step

We first translate this sentence into an algebraic equation. The first part of the problem wants us to multiply a number by $-6$, so we have: $x(-6)$ We rearrange this expression to make it look more conventional: $-6x$ The other part of the equation is that this expression should be made equal to $20$, so we have now: $-6x = 20$ Now, we solve the equation for $x$ by dividing both sides by $-6$: $x = -\frac{20}{6}$ We can simplify the answer by reducing the fraction (dividing both the numerator and denominator by $2$): $x = -\frac{10}{3}$
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