Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.2 - The Multiplication Property of Equality - Exercise Set - Page 130: 37



Work Step by Step

$12=4z+3$ $4z+3=12$ First subtract 3 from both sides. $4z=12-3$ $4z=9$ Then divide both sides by 4. 4z$\div$4=9$\div$4 z=$\frac{9}{4}$ Check the answer. 12=4($\frac{9}{4}$)+3 12=9+3 12=12
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