## Introductory Algebra for College Students (7th Edition)

z=$\frac{9}{4}$
$12=4z+3$ $4z+3=12$ First subtract 3 from both sides. $4z=12-3$ $4z=9$ Then divide both sides by 4. 4z$\div$4=9$\div$4 z=$\frac{9}{4}$ Check the answer. 12=4($\frac{9}{4}$)+3 12=9+3 12=12