Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.2 - The Multiplication Property of Equality - Exercise Set - Page 130: 50



Work Step by Step

$6z-3=z+2$ First add 3 to both sides. $6z=z+2+3$ $6z=z+5$ Then subtract z from both sides. $6z-z=5$ $5z=5$ Then divide both sides by 5. 5z$\div$5=5$\div$5 $z=1$ Check the answer. 6(1)-3=(1)+2 6-3=3 3=3
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