## Introductory Algebra for College Students (7th Edition)

$y=-6$
$5y+6=3y-6$ First subtract 6 from both sides. $5y=3y-6-6$ $5y=3y-12$ Then subtract 2y from both sides. $5y-3y=-12$ $2y=-12$ Then divide both sides by 2. 2y$\div$2=-12$\div$2 $y=-6$ Check the answer. 5(-6)+6=3(-6)-6 -30+6=-18-6 -24=-24