Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.2 - The Multiplication Property of Equality - Exercise Set - Page 130: 49

Answer

$z=2$

Work Step by Step

$6z-5=z+5$ First add 5 to both sides. $6z=z+5+5$ $6z=z+10$ Then subtract z from both sides. $6z-z=10$ $5z=10$ Then divide both sides by 5. 5z$\div$5=10$\div$5 $z=2$ Check the answer. 6(2)-5=(2)+5 12-5=2+5 7=7
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