## Introductory Algebra for College Students (7th Edition)

y=-$\frac{3}{2}$
$8y+4=2y-5$ First subtract 4 from both sides. $8y=2y-5-4$ $8y=2y-9$ Then subtract 2y from both sides. $8y-2y=-9$ $6y=-9$ Then divide both sides by 6. $\frac{6y}{6}$=$\frac{-9}{6}$ y=-$\frac{3}{2}$ Check the answer. 8(-$\frac{3}{2}$)+4=2(-$\frac{3}{2}$)-5 -(4)(3)+4=-3-5 -12+4=-8 -8=-8