Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.2 - The Multiplication Property of Equality - Exercise Set - Page 130: 47



Work Step by Step

$8y+4=2y-5$ First subtract 4 from both sides. $8y=2y-5-4$ $8y=2y-9$ Then subtract 2y from both sides. $8y-2y=-9$ $6y=-9$ Then divide both sides by 6. $\frac{6y}{6}$=$\frac{-9}{6}$ y=-$\frac{3}{2}$ Check the answer. 8(-$\frac{3}{2}$)+4=2(-$\frac{3}{2}$)-5 -(4)(3)+4=-3-5 -12+4=-8 -8=-8
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.