Answer
a. The graph estimates it as $16.2$. Therefore the equation overestimates the data displayed by the graph by about $0.3$
b. $x=11$ years after, at $2017$
Work Step by Step
$f(x)=1.2\ln x+15.7$
a. At $2008, x=2$
$f(2)=1.2\ln 2+15.7=16.5$
The graph estimates it as $16.2$. Therefore the equation overestimates the data displayed by the graph by about $0.3$
b. $f(x)=1.2\ln x+15.7=18.6$
$1.2\ln x=2.9$
$\ln x=2.42$
$x=11.25$
Thus, $x=11$ years after, at $2017$.
