Answer
$r=0.157=15.7\%$
Work Step by Step
$P=2350, A=3p=7050, t=7$
$A=Pe^{rt}$
$A=2350e^{7r}=7050$
$e^{7r}=3$
$7r=\ln 3$
$r=0.157=15.7\%$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set - Page 728: 109
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