Answer
$r=0.203=20.3\%$
Work Step by Step
$P=8000, A=12000, t=2$
$A=Pe^{rt}$
$A=8000e^{2r}=12000$
$e^{2r}=1.5$
$2r=\ln 1.5$
$r=0.203=20.3\%$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 9 - Section 9.5 - Exponential and Logarithmic Equations - Exercise Set - Page 728: 108
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