Answer
a. The graph estimates it as $17.3$. Therefore the equation underestimates the data displayed by the graph by about $0.3$
b. $x=10$ years after at $2016$
Work Step by Step
$f(x)=1.2\ln x+15.7$
a. At $2009, x=3$
$f(3)=1.2\ln 3+15.7=17.0$
The graph estimates it as $17.3$. Therefore the equation underestimates the data displayed by the graph by about $0.3$
b. $f(x)=1.2\ln x+15.7=18.5$
$1.2\ln x=2.8$
$\ln x=2.333$
$x=10.31$
Thus, $x=10$ years after, at $2016$
