Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.4 - Properties of Logarithms - Exercise Set: 41

Answer

$5$

Work Step by Step

RECALL: $\log_b{a}-\log_b{c} = \log_b{(\frac{a}{c})}$ Use the rule above to obtain: $=\log_2{(\frac{96}{3})} \\=\log_2{32}$ Write $32$ as $2^5$ to obtain: $=\log_2{2^5}$ Use the rule $\log_b{b^x} = x$ to obtain: $=5$
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