## Intermediate Algebra for College Students (7th Edition)

$\log_8{(13 \cdot 7)} = \log_8{13} + \log_8{7}$
RECALL: The product rule for logarithms: $\log_a{bc} = \log_a{b} + \log_a{c}$ Use the product rule to obtain: $\log_8{(13 \cdot 7)} = \log_8{13} + \log_8{7}$