## Intermediate Algebra for College Students (7th Edition)

$\frac{1}{7}\cdot\ln{x}$
Use the rule $\sqrt[n]{a} = a^{\frac{1}{n}}$ to obtain: $=\ln{(x^{\frac{1}{7}})}$ RECALL: The power rule for logarithms states: $\ln{(b^c)}=c \cdot \ln{b}$ Use the rule above to obtain: $=\frac{1}{7}\cdot\ln{x}$