## Intermediate Algebra for College Students (7th Edition)

$3$
RECALL: $\log{a}+\log{b} = \log{ab}$ Use the rule above to obtain: $=\log{(250\cdot 4)} \\=\log{1000}$ Write $1000$ as $10^3$ to obtain: $=\log{10^3}$ Use the rule $\log{10^x} = x$ to obtain: $=3$