Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.4 - Properties of Logarithms - Exercise Set: 37

Answer

$1$

Work Step by Step

RECALL: $\log{a}+\log{b} = \log{ab}$ Use the rule above to obtain: $=\log{(5\cdot2)} \\=\log{10}$ Use the rule $\log{10} = 1$ to obtain: $=1$
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