## Intermediate Algebra for College Students (7th Edition)

$2-\ln{5}$
RECALL: The quotient rule for logarithms states: $\ln(\frac{b}{c})=\ln{b}−\ln{c}$ Use the quotient rule to obtain: $=\ln(e^2))-\ln{5}$ Note that for all real numbers within its domain, $\ln{(e^n)}=n$. This means that $\ln{(e^2)}=2$. Thus, $\ln{(e^2)}-\ln{5}=2-\ln{5}$