Answer
$f^{-1}(x)=x^{\frac{5}{3}}$
Work Step by Step
$f(x)=x^{\frac{3}{5}}$
$y=x^{\frac{3}{5}}$
a.
$x=y^{\frac{3}{5}}$
$x^{\frac{5}{3}}=y$
$f^{-1}(x)=x^{\frac{5}{3}}$
b.
$f(f^{-1}(x))=(x^{\frac{3}{5}})^{\frac{5}{3}}=x$
and
$f^{-1}(f(x))=(x^{\frac{5}{3}})^{\frac{3}{5}}=x$
