Answer
$f^{-1}(x)=\frac{x+1}{3}$
Work Step by Step
$f(x)=3x-1$
$y=3x-1$
a.
$x=3y-1$
$x+1=3y$
$f^{-1}(x)=\frac{x+1}{3}$
b.
$f(f^{-1}(x)))=3\left(\frac{x+1}{3}\right)-1=x$
and
$f^{-1}(f(x))=\frac{3x-1+1}{3}=x$
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