Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.2 - Composite and Inverse Functions - Exercise Set - Page 687: 29

Answer

$f^{-1}(x)=\frac{x-3}{2}$

Work Step by Step

$f(x)=2x+3,$ $y=2x+3$ a. $x=2y+3$ $x-3=2y$ $f^{-1}(x)=\frac{x-3}{2}$ b. $f(f^{-1}(x)))=2\left(\frac{x-3}{2}\right)+3=x$ and $f^{-1}(f(x))=\frac{2x+3-3}{2}=x$
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