Answer
$f^{-1}(x)=\frac{x-3}{2}$
Work Step by Step
$f(x)=2x+3,$
$y=2x+3$
a.
$x=2y+3$
$x-3=2y$
$f^{-1}(x)=\frac{x-3}{2}$
b.
$f(f^{-1}(x)))=2\left(\frac{x-3}{2}\right)+3=x$
and
$f^{-1}(f(x))=\frac{2x+3-3}{2}=x$
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