Answer
$f^{-1}(x)=\frac{x}{4}$
Work Step by Step
$f(x)=4x$
$y=4x$
a.
$x=4y$
$\frac{x}{4}=y$
$f^{-1}(x)=\frac{x}{4}$
b.
$f(f^{-1}(x)))=4(\frac{x}{4})=x$
and
$f^{-1}(f(x))=\frac{4x}{4}=x$
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