Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 51

Answer

$-5 + 12i$

Work Step by Step

RECALL: (1) $(a+b)^2 = a^2+ 2ab + b^2$ (2) $i^2=-1$ Use rule (1) above with $a=2$ and $b=3i$ to obtain: $=2^2 +2(2)(3i) + (3i)^2 \\=4 +12i + 9i^2$ Use rule (2) above to obtain: $=4 +12i + 9(-1) \\=4+12i+(-9) \\=-5 + 12i$
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