Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 79

Answer

$-\dfrac{7}{3}i$

Work Step by Step

Multiply both the numerator and the denominator by the conjugate of the denominator, which is $-3i$, to obtain: $=\dfrac{7(-3i)}{3i(-3i)} \\=\dfrac{-21i}{-9i^2}$ Use the fact that $i^2=-1$ to obtain: $=\dfrac{-21i}{-9(-1)} \\=\dfrac{-21i}{9} \\=-\dfrac{21}{9}i \\=-\dfrac{7}{3}i$
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