Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 49

Answer

$11$

Work Step by Step

RECALL: (1) $(a-b)(a+b) = a^2-b^2$ (2) $i^2=-1$ Use rule (1) above with $a=3$ and $b=i\sqrt{2}$ to obtain: $=3^2 - (i\sqrt{2})^2 \\=9 - i^2(2)$ Use rule (2) above to obtain: $=9 - (-1)(2) \\=9-(-2) \\=9+2 \\=11$
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