Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 33

Answer

$-6 + 10i$

Work Step by Step

RECALL: (1) $a(b+c) = ac + bc$ (2) $i^2=-1$ Use rule (1) above to obtain: $=2i(5) + 2i(3i) \\=10i + 6i^2$ Use rule (2) above to obtain: $=10i + 6(-1) \\=10i +(-6) \\=-6 + 10i$
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