Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set: 13

Answer

$13+i\sqrt{3}$

Work Step by Step

Factor the radicand so that one factor $-1$ to obtain: $=13+\sqrt{3(-1)}$ RECALL: (1) $\sqrt{ab} = \sqrt{a} \cdot \sqrt{b}$ (2) $\sqrt{-1} = i$ Use rule (1) above to obtain: $=13+ \sqrt{3} \cdot \sqrt{-1}$ Use rule (2) above to obtain: $=13+\sqrt{3} \cdot i \\=13+i\sqrt{3}$
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