Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.6 - Radical Equations - Exercise Set: 45

Answer

$l=\dfrac{8t^2}{\pi^2}$

Work Step by Step

Divide $2\pi$ on both sides to obtain: $\dfrac{t}{2\pi}=\sqrt{\dfrac{l}{32}}$ Square both sides to obtain: $\dfrac{t^2}{4\pi^2}=\dfrac{l}{32}$ Multiply $32$ on both sides to obtain: $\require{cancel} 32 \cdot \dfrac{t^2}{4\pi^2} = \dfrac{lA}{32} \cdot 32 \\\dfrac{8\cancel{32}t^2}{\cancel{4}\pi^2} = \dfrac{l}{\cancel{32}} \cdot \cancel{32} \\\dfrac{8t^2}{\pi^2} = l$
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