Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.6 - Radical Equations - Exercise Set - Page 560: 42

Answer

$ 4$.

Work Step by Step

The given functions are $f(x)=(9x+2)^{\frac{1}{4}}$ and $g(x)=(5x+18)^{\frac{1}{4}}$ Equate both functions $\Rightarrow f(x)=g(x)$ $\Rightarrow (9x+2)^{\frac{1}{4}}=(5x+18)^{\frac{1}{4}}$ Raise the power to $4$ on both sides. $\Rightarrow \left [(9x+2)^{\frac{1}{4}}\right ]^4=\left [(5x+18)^{\frac{1}{4}}\right ]^4$ Multiply exponents on both sides. $\Rightarrow 9x+2=5x+18$ Add $-5x-2$ to both sides. $\Rightarrow 9x+2-5x-2=5x+18-5x-2$ Simplify. $\Rightarrow 4x=16$ Divide both sides by $4$. $\Rightarrow \frac{4x}{4}=\frac{16}{4}$ Simplify. $\Rightarrow x=4$.
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