## Intermediate Algebra for College Students (7th Edition)

$x=8$
RECALL: For any non-negative real number $a$, $\left(a^{\frac{1}{4}}\right)^4=a$ Raise both sides of the equation to the fourth power then sue the rule above to simplify. $\left((x+8)^{\frac{1}{4}}\right)^4=\left((2x)^{\frac{1}{4}}\right)^4 \\x+8=2x$ Subtract $x$ on both sides of the equation to obtain: $8=2x-x$ $8=x$