Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.6 - Radical Equations - Exercise Set: 37

Answer

$x=8$

Work Step by Step

RECALL: For any non-negative real number $a$, $\left(a^{\frac{1}{4}}\right)^4=a$ Raise both sides of the equation to the fourth power then sue the rule above to simplify. $\left((x+8)^{\frac{1}{4}}\right)^4=\left((2x)^{\frac{1}{4}}\right)^4 \\x+8=2x$ Subtract $x$ on both sides of the equation to obtain: $8=2x-x$ $8=x$
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