Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.6 - Radical Equations - Exercise Set: 29

Answer

$x=5$

Work Step by Step

Subtract 7 on both sides to obtain: $(3x+1)^{\frac{1}{4}}=2$ Raise both sides to the fourth power obtain: $\left((3x+1)^{\frac{1}{4}}\right)^4=2^4 \\(3x+1)^{\frac{1}{4}(4)}=16 \\(3x+1)^1=16 \\3x+1=16$ Subtract 1 on both sides to obtain: $3x=15$ Divide 3 on both sides to obtain: $x = 5$
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