Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.6 - Radical Equations - Exercise Set - Page 560: 31


no solution

Work Step by Step

Subtract 8 on both sides to obtain: $(x+2)^{\frac{1}{2}}=-4$ RECALL: (1) $a^{\frac{1}{2}}=\sqrt{a}$ (2) For any real number $a$, $\sqrt{a} \ge 0$ Use rule (1) above to obtain: $\sqrt{x+2} = -4$ According to rule (2) above, the principal square root of any real number cannot be negative. with a negative number on the right side of the equation, the given equation has no solution.
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