## Intermediate Algebra for College Students (7th Edition)

Subtract 8 on both sides to obtain: $(x+2)^{\frac{1}{2}}=-4$ RECALL: (1) $a^{\frac{1}{2}}=\sqrt{a}$ (2) For any real number $a$, $\sqrt{a} \ge 0$ Use rule (1) above to obtain: $\sqrt{x+2} = -4$ According to rule (2) above, the principal square root of any real number cannot be negative. with a negative number on the right side of the equation, the given equation has no solution.