## Intermediate Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set - Page 530: 6

#### Answer

$\sqrt[5]{27}$

#### Work Step by Step

RECALL: For nonegative numbers a and b, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ Use the rule above to obtain: $=\sqrt[5]{9\cdot3} \\=\sqrt[5]{27}$

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