Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set: 11

Answer

$\sqrt{x^2-9}$

Work Step by Step

RECALL: (i) For nonegative numbers a and b, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ (ii) $(a+b)(a-b)=a^{2}-b^2$ Use the rules above to obtain: $=\sqrt{(x+3)(x-3)} \\\\=\sqrt{x^{2}-3^{2}}$ $\\=\sqrt{x^2-9}$
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