#### Answer

$\sqrt{x}$

#### Work Step by Step

RECALL:
For nonegative numbers a and b,
$\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$
Use the rule above to obtain:
$\require{cancel}
\\=\sqrt{\dfrac{2x}{3} \cdot \dfrac{3}{2}}
\\=\sqrt{\dfrac{\cancel{2}x}{\cancel{3}} \cdot \dfrac{\cancel{3}}{\cancel{2}}}
\\=\sqrt{x}$