Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set: 16

Answer

$\sqrt{x}$

Work Step by Step

RECALL: For nonegative numbers a and b, $\sqrt[n]{a} \cdot \sqrt[n]{b} = \sqrt[n]{ab}$ Use the rule above to obtain: $\require{cancel} \\=\sqrt{\dfrac{2x}{5} \cdot \dfrac{5}{2}} \\=\sqrt{\dfrac{\cancel{2}x}{\cancel{5}} \cdot \dfrac{\cancel{5}}{\cancel{2}}} \\=\sqrt{x}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.