Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set - Page 530: 1



Work Step by Step

RECALL: For nonegative numbers a and b, $\sqrt{a} \cdot \sqrt{b} = \sqrt{ab}$ Use the rule above to obtain: $=\sqrt{3\cdot5} \\=\sqrt{15}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.