Answer
$\frac{5(x+1)}{3}$.
Work Step by Step
The given expression is
$=\frac{5x^2-5}{3x+12}\cdot \frac{x+4}{x-1}$
Factor $5x^2-5$.
$=5(x^2-1)$
$=5(x^2-1^2)$
Use the algebraic identity $a^2-b^2=(a+b)(a-b)$.
$=5(x+1)(x-1)$.
Factor $3x+12$.
$=3(x+4)$
Substitute all factors into the given expression.
$=\frac{5(x+1)(x-1)}{3(x+4)}\cdot \frac{x+4}{x-1}$
Cancel common terms.
$=\frac{5(x+1)}{3}$.
