Answer
$\frac{x-1}{x-7}$ and $x\ne-7$.
Work Step by Step
$\frac{x^2+6x-7}{x^2-49}=\frac{x^2-x+7x-7}{x^2-49}=\frac{x(x-1)+7(x-1)}{x^2-49}=\frac{(x-1)(x+7)}{(x+7)(x-7)}=\frac{x-1}{x-7}$ and $x\ne-7$.
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Review Exercises - Page 496: 5
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