Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 6 - Review Exercises - Page 496: 4

Answer

$\frac{x^2-7}{3x}$

Work Step by Step

$\frac{5x^3-35x}{15x^2}=\frac{5x(x^2-7)}{5x\cdot3x}=\frac{x^2-7}{3x}$
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